(8x+7)(x^2-5x-8)=0

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Solution for (8x+7)(x^2-5x-8)=0 equation: 


Simplifying
(8x + 7)(x2 + -5x + -8) = 0

Reorder the terms:
(7 + 8x)(x2 + -5x + -8) = 0

Reorder the terms:
(7 + 8x)(-8 + -5x + x2) = 0

Multiply (7 + 8x) * (-8 + -5x + x2)
(7(-8 + -5x + x2) + 8x * (-8 + -5x + x2)) = 0
((-8 * 7 + -5x * 7 + x2 * 7) + 8x * (-8 + -5x + x2)) = 0
((-56 + -35x + 7x2) + 8x * (-8 + -5x + x2)) = 0
(-56 + -35x + 7x2 + (-8 * 8x + -5x * 8x + x2 * 8x)) = 0
(-56 + -35x + 7x2 + (-64x + -40x2 + 8x3)) = 0

Reorder the terms:
(-56 + -35x + -64x + 7x2 + -40x2 + 8x3) = 0

Combine like terms: -35x + -64x = -99x
(-56 + -99x + 7x2 + -40x2 + 8x3) = 0

Combine like terms: 7x2 + -40x2 = -33x2
(-56 + -99x + -33x2 + 8x3) = 0

Solving
-56 + -99x + -33x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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